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I believe the 16C55 used parallel programming instead of the serial programming so new serial only programmers will not work.

bulut_01,
Where did you get your repeated references to UART and KEELOQ from?

You have made a lot of statements about what you have for hardware. Many of those don't seem accurate. Only you know what you have, or maybe you are not even sure.

When you read the pin state, toggle a different output pin. Look at both the input pin and output pin on a logic analyzer to see if you are sampling at the correct time in the bit.

The reason Manchester encoding exists and why it is used is that the clock is imbedded in the data. You don't have to know the exact clock or bit rate you just have to be somewhat close (+/- 20%). T ...

On your logic capture, remove the UART decoding as it is invalid and is causing confusion.

It is so shocking to see framing errors ("!") in the data when you are trying to read data that is not UART formatted...

0xD5 is a problem. binary 11010101 -> 11 01 01 01
11 and 00 are not valid for Manchester. Only 10 or 01 are allowed.
Each bit is either a high to low transition or low to high transition with t ...

A Manchester bit stream cannot be read in through a UART.
Start over and read the bit stream in correctly.
No amount of software can fix permanently corrupted data, which is what you get trying to u ...

bulut_01
How are you reading the bit stream into the PIC processor?

UART has a start and stop bit for every byte. 10 bits make a byte
Manchester is a continuous stream of bits. The bytes are not separated.

Also,
0x66 0xA6 0x55 0x35 0xD3 0x2D 0x6A 0x65 0x59 0xD8
cannot be Manchester encoded as 0xD, 0x3, 0x8, 0x2 are invalid.

In Manchester each bit is either a 01 binary or 10 binary.
0x66 is 01100110 binary so it decodes to either hex A or hex 5

sifirzero1,
Have you ever written code for a PIC processor before?
You seem to not have an understanding of the processor operation or programming.

You can count the number of cycles received in a set amount of time or you can measure the time for one or move cycles to complete.

Since you haven't answered the previous requests for details the ...